Base | Representation |
---|---|
bin | 1011101110000011010… |
… | …0010010101011101011 |
3 | 201020200202021222110120 |
4 | 2323200310102223223 |
5 | 11244321104100021 |
6 | 232254445214323 |
7 | 20355254212134 |
oct | 2734064225353 |
9 | 636622258416 |
10 | 201340300011 |
11 | 7842a394464 |
12 | 330305613a3 |
13 | 15ca8bc73c6 |
14 | 9a600d2c8b |
15 | 5385e752c6 |
hex | 2ee0d12aeb |
201340300011 has 8 divisors (see below), whose sum is σ = 270567542784. Its totient is φ = 133169961960.
The previous prime is 201340300009. The next prime is 201340300019. The reversal of 201340300011 is 110003043102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 201340300011 - 21 = 201340300009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201340300019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 264225735 + ... + 264226496.
It is an arithmetic number, because the mean of its divisors is an integer number (33820942848).
Almost surely, 2201340300011 is an apocalyptic number.
201340300011 is a deficient number, since it is larger than the sum of its proper divisors (69227242773).
201340300011 is a wasteful number, since it uses less digits than its factorization.
201340300011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 528452361.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 201340300011 its reverse (110003043102), we get a palindrome (311343343113).
The spelling of 201340300011 in words is "two hundred one billion, three hundred forty million, three hundred thousand, eleven".
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