Base | Representation |
---|---|
bin | 11101010011001000001… |
… | …100000100110110000111 |
3 | 21010110221112112012112221 |
4 | 131103020030010312013 |
5 | 230441422221201203 |
6 | 4140540020153211 |
7 | 265315003463050 |
oct | 35231014046607 |
9 | 7113845465487 |
10 | 2013403303303 |
11 | 706974747a57 |
12 | 286264838807 |
13 | 117b2b363082 |
14 | 6d6409dd727 |
15 | 3758ea46abd |
hex | 1d4c8304d87 |
2013403303303 has 8 divisors (see below), whose sum is σ = 2340032895360. Its totient is φ = 1696523848440.
The previous prime is 2013403303283. The next prime is 2013403303319. The reversal of 2013403303303 is 3033033043102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013403303303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013403303333) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2437533853 + ... + 2437534678.
It is an arithmetic number, because the mean of its divisors is an integer number (292504111920).
Almost surely, 22013403303303 is an apocalyptic number.
2013403303303 is a deficient number, since it is larger than the sum of its proper divisors (326629592057).
2013403303303 is an equidigital number, since it uses as much as digits as its factorization.
2013403303303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4875068597.
The product of its (nonzero) digits is 5832, while the sum is 25.
Adding to 2013403303303 its reverse (3033033043102), we get a palindrome (5046436346405).
The spelling of 2013403303303 in words is "two trillion, thirteen billion, four hundred three million, three hundred three thousand, three hundred three".
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