Base | Representation |
---|---|
bin | 101101110001111000110011… |
… | …100111111101100011001001 |
3 | 222101212221121200111001021110 |
4 | 231301320303213331203021 |
5 | 202342230010303000000 |
6 | 1552114250544000533 |
7 | 60260234252054442 |
oct | 5561706347754311 |
9 | 871787550431243 |
10 | 201340343015625 |
11 | 59175a61778270 |
12 | 1a6b9135600149 |
13 | 884640b5179a8 |
14 | 37a0cd314a2c9 |
15 | 18424ceb55850 |
hex | b71e339fd8c9 |
201340343015625 has 112 divisors (see below), whose sum is σ = 371083373822016. Its totient is φ = 96282288000000.
The previous prime is 201340343015621. The next prime is 201340343015627. The reversal of 201340343015625 is 526510343043102.
It is not a de Polignac number, because 201340343015625 - 22 = 201340343015621 is a prime.
It is not an unprimeable number, because it can be changed into a prime (201340343015621) by changing a digit.
It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 34966117 + ... + 40315133.
Almost surely, 2201340343015625 is an apocalyptic number.
201340343015625 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
201340343015625 is a deficient number, since it is larger than the sum of its proper divisors (169743030806391).
201340343015625 is an frugal number, since it uses more digits than its factorization.
201340343015625 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5349134 (or 5349109 counting only the distinct ones).
The product of its (nonzero) digits is 259200, while the sum is 39.
Adding to 201340343015625 its reverse (526510343043102), we get a palindrome (727850686058727).
The spelling of 201340343015625 in words is "two hundred one trillion, three hundred forty billion, three hundred forty-three million, fifteen thousand, six hundred twenty-five".
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