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20134041423 = 36711347141
BaseRepresentation
bin10010110000000101…
…010001011101001111
31220222011202021111220
4102300011101131033
5312213303311143
613125514214423
71311640346136
oct226005213517
956864667456
1020134041423
1185a2161361
123a9aa24413
131b8b3a9aa2
14d9001891d
157cc8e6d83
hex4b015174f

20134041423 has 4 divisors (see below), whose sum is σ = 26845388568. Its totient is φ = 13422694280.

The previous prime is 20134041407. The next prime is 20134041449. The reversal of 20134041423 is 32414043102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20134041423 - 24 = 20134041407 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20134041393 and 20134041402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20134041623) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355673568 + ... + 3355673573.

It is an arithmetic number, because the mean of its divisors is an integer number (6711347142).

Almost surely, 220134041423 is an apocalyptic number.

20134041423 is a deficient number, since it is larger than the sum of its proper divisors (6711347145).

20134041423 is an equidigital number, since it uses as much as digits as its factorization.

20134041423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6711347144.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 20134041423 its reverse (32414043102), we get a palindrome (52548084525).

The spelling of 20134041423 in words is "twenty billion, one hundred thirty-four million, forty-one thousand, four hundred twenty-three".

Divisors: 1 3 6711347141 20134041423