2013404404331 has 2 divisors, whose sum is σ = 2013404404332. Its totient is φ = 2013404404330.

The previous prime is 2013404404267. The next prime is 2013404404337. The reversal of 2013404404331 is 1334044043102.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013404404331 - 2⁶ = 2013404404267 is a prime.

It is a super-2 number, since 2×2013404404331² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013404404294 and 2013404404303.

It is not a weakly prime, because it can be changed into another prime (2013404404337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006702202165 + 1006702202166.

It is an arithmetic number, because the mean of its divisors is an integer number (1006702202166).

Almost surely, 2^{2013404404331} is an apocalyptic number.

2013404404331 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013404404331 is an equidigital number, since it uses as much as digits as its factorization.

2013404404331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 2013404404331 its reverse (1334044043102), we get a palindrome (3347448447433).

The spelling of 2013404404331 in words is "two trillion, thirteen billion, four hundred four million, four hundred four thousand, three hundred thirty-one".