201341010001 has 4 divisors (see below), whose sum is σ = 201341972404. Its totient is φ = 201340047600.

The previous prime is 201341009999. The next prime is 201341010023. The reversal of 201341010001 is 100010143102.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 42797679376 + 158543330625 = 206876^2 + 398175^2 .

It is a cyclic number.

It is not a de Polignac number, because 201341010001 - 2¹ = 201341009999 is a prime.

It is a super-3 number, since 3×201341010001³ (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201341010061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20130 + ... + 634891.

It is an arithmetic number, because the mean of its divisors is an integer number (50335493101).

Almost surely, 2^201341010001 is an apocalyptic number.

It is an amenable number.

201341010001 is a deficient number, since it is larger than the sum of its proper divisors (962403).

201341010001 is an equidigital number, since it uses as much as digits as its factorization.

201341010001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 962402.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 201341010001 its reverse (100010143102), we get a palindrome (301351153103).

The spelling of 201341010001 in words is "two hundred one billion, three hundred forty-one million, ten thousand, one".