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2013410101323 = 3671136700441
BaseRepresentation
bin11101010011001000100…
…110000000100001001011
321010110222000022120200110
4131103020212000201023
5230441430441220243
64140540422005403
7265315115325255
oct35231046004113
97113860276613
102013410101323
11706978570455
12286266b76863
13117b2c8a337a
146d64188ccd5
153759043ae33
hex1d4c898084b

2013410101323 has 4 divisors (see below), whose sum is σ = 2684546801768. Its totient is φ = 1342273400880.

The previous prime is 2013410101309. The next prime is 2013410101369. The reversal of 2013410101323 is 3231010143102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 2013410101323 - 26 = 2013410101259 is a prime.

It is a super-2 number, since 2×20134101013232 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2013410101323.

It is not an unprimeable number, because it can be changed into a prime (2013410108323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335568350218 + ... + 335568350223.

It is an arithmetic number, because the mean of its divisors is an integer number (671136700442).

Almost surely, 22013410101323 is an apocalyptic number.

2013410101323 is a deficient number, since it is larger than the sum of its proper divisors (671136700445).

2013410101323 is an equidigital number, since it uses as much as digits as its factorization.

2013410101323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671136700444.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 2013410101323 its reverse (3231010143102), we get a palindrome (5244420244425).

The spelling of 2013410101323 in words is "two trillion, thirteen billion, four hundred ten million, one hundred one thousand, three hundred twenty-three".

Divisors: 1 3 671136700441 2013410101323