2013410101322 has 4 divisors (see below), whose sum is σ = 3020115151986. Its totient is φ = 1006705050660.

The previous prime is 2013410101309. The next prime is 2013410101369. The reversal of 2013410101322 is 2231010143102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1492528899481 + 520881201841 = 1221691^2 + 721721^2 .

It is a super-2 number, since 2×2013410101322² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013410101294 and 2013410101303.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503352525329 + ... + 503352525332.

Almost surely, 2^{2013410101322} is an apocalyptic number.

2013410101322 is a deficient number, since it is larger than the sum of its proper divisors (1006705050664).

2013410101322 is a wasteful number, since it uses less digits than its factorization.

2013410101322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1006705050663.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 2013410101322 its reverse (2231010143102), we get a palindrome (4244420244424).

The spelling of 2013410101322 in words is "two trillion, thirteen billion, four hundred ten million, one hundred one thousand, three hundred twenty-two".