Base | Representation |
---|---|
bin | 1011101110000011011… |
… | …1000000010101001001 |
3 | 201020200210122010010121 |
4 | 2323200313000111021 |
5 | 11244321244330043 |
6 | 232254512343241 |
7 | 20355263233603 |
oct | 2734067002511 |
9 | 636623563117 |
10 | 201341011273 |
11 | 7842a82a886 |
12 | 33030844b21 |
13 | 15ca90b607c |
14 | 9a6023a173 |
15 | 5386065ded |
hex | 2ee0dc0549 |
201341011273 has 2 divisors, whose sum is σ = 201341011274. Its totient is φ = 201341011272.
The previous prime is 201341011127. The next prime is 201341011367. The reversal of 201341011273 is 372110143102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 159239306304 + 42101704969 = 399048^2 + 205187^2 .
It is a cyclic number.
It is not a de Polignac number, because 201341011273 - 237 = 63902057801 is a prime.
It is not a weakly prime, because it can be changed into another prime (201341011373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670505636 + 100670505637.
It is an arithmetic number, because the mean of its divisors is an integer number (100670505637).
Almost surely, 2201341011273 is an apocalyptic number.
It is an amenable number.
201341011273 is a deficient number, since it is larger than the sum of its proper divisors (1).
201341011273 is an equidigital number, since it uses as much as digits as its factorization.
201341011273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 201341011273 its reverse (372110143102), we get a palindrome (573451154375).
The spelling of 201341011273 in words is "two hundred one billion, three hundred forty-one million, eleven thousand, two hundred seventy-three".
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