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2013410410413 = 3671136803471
BaseRepresentation
bin11101010011001000100…
…111001011111110101101
321010110222000220021200020
4131103020213023332231
5230441431031113123
64140540432352353
7265315121053353
oct35231047137655
97113860807606
102013410410413
117069787616a6
122862670a56b9
13117b2c980c6c
146d64192d7d3
153759049c7e3
hex1d4c89cbfad

2013410410413 has 4 divisors (see below), whose sum is σ = 2684547213888. Its totient is φ = 1342273606940.

The previous prime is 2013410410367. The next prime is 2013410410469. The reversal of 2013410410413 is 3140140143102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013410410413 - 28 = 2013410410157 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013410411413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335568401733 + ... + 335568401738.

It is an arithmetic number, because the mean of its divisors is an integer number (671136803472).

Almost surely, 22013410410413 is an apocalyptic number.

It is an amenable number.

2013410410413 is a deficient number, since it is larger than the sum of its proper divisors (671136803475).

2013410410413 is an equidigital number, since it uses as much as digits as its factorization.

2013410410413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671136803474.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 2013410410413 its reverse (3140140143102), we get a palindrome (5153550553515).

The spelling of 2013410410413 in words is "two trillion, thirteen billion, four hundred ten million, four hundred ten thousand, four hundred thirteen".

Divisors: 1 3 671136803471 2013410410413