Base | Representation |
---|---|
bin | 1001001001111110101101… |
… | …00111001001000001010101 |
3 | 2122021210122220102021221020 |
4 | 10210333112213021001111 |
5 | 10114334130222114031 |
6 | 110453252234111353 |
7 | 4145433033540246 |
oct | 444772647110125 |
9 | 78253586367836 |
10 | 20134112301141 |
11 | 6462913553953 |
12 | 231216157b559 |
13 | b3083c139847 |
14 | 4d86d3950ccd |
15 | 24db03c54096 |
hex | 124fd69c9055 |
20134112301141 has 16 divisors (see below), whose sum is σ = 27527050213824. Its totient is φ = 13086088671744.
The previous prime is 20134112301139. The next prime is 20134112301143. The reversal of 20134112301141 is 14110321143102.
It is an interprime number because it is at equal distance from previous prime (20134112301139) and next prime (20134112301143).
It is not a de Polignac number, because 20134112301141 - 21 = 20134112301139 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20134112301143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 516319230 + ... + 516358223.
It is an arithmetic number, because the mean of its divisors is an integer number (1720440638364).
Almost surely, 220134112301141 is an apocalyptic number.
It is an amenable number.
20134112301141 is a deficient number, since it is larger than the sum of its proper divisors (7392937912683).
20134112301141 is a wasteful number, since it uses less digits than its factorization.
20134112301141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1032677620.
The product of its (nonzero) digits is 576, while the sum is 24.
Adding to 20134112301141 its reverse (14110321143102), we get a palindrome (34244433444243).
The spelling of 20134112301141 in words is "twenty trillion, one hundred thirty-four billion, one hundred twelve million, three hundred one thousand, one hundred forty-one".
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