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201341123431 = 724109002519
BaseRepresentation
bin1011101110000011011…
…1011011101101100111
3201020200210211210222121
42323200313123231213
511244321311422211
6232254515010411
720355264211600
oct2734067335547
9636623753877
10201341123431
117842a8a7078
1233030899a07
1315ca9125136
149a60268da7
155386089271
hex2ee0ddbb67

201341123431 has 6 divisors (see below), whose sum is σ = 234213143640. Its totient is φ = 172578105756.

The previous prime is 201341123363. The next prime is 201341123443. The reversal of 201341123431 is 134321143102.

It is not a de Polignac number, because 201341123431 - 219 = 201340599143 is a prime.

It is a super-2 number, since 2×2013411234312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201341123396 and 201341123405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201341123461) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2054501211 + ... + 2054501308.

It is an arithmetic number, because the mean of its divisors is an integer number (39035523940).

Almost surely, 2201341123431 is an apocalyptic number.

201341123431 is a deficient number, since it is larger than the sum of its proper divisors (32872020209).

201341123431 is an equidigital number, since it uses as much as digits as its factorization.

201341123431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4109002533 (or 4109002526 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 201341123431 its reverse (134321143102), we get a palindrome (335662266533).

The spelling of 201341123431 in words is "two hundred one billion, three hundred forty-one million, one hundred twenty-three thousand, four hundred thirty-one".

Divisors: 1 7 49 4109002519 28763017633 201341123431