Base | Representation |
---|---|
bin | 10010110000000101… |
… | …111000110010111011 |
3 | 1220222012001110112202 |
4 | 102300011320302323 |
5 | 312213323440210 |
6 | 13125521500415 |
7 | 1311641616665 |
oct | 226005706273 |
9 | 56865043482 |
10 | 20134202555 |
11 | 85a2261425 |
12 | 3a9aaa170b |
13 | 1b8b43522c |
14 | d9005b535 |
15 | 7cc9299a5 |
hex | 4b0178cbb |
20134202555 has 32 divisors (see below), whose sum is σ = 25293772800. Its totient is φ = 15367968000.
The previous prime is 20134202533. The next prime is 20134202573. The reversal of 20134202555 is 55520243102.
It is a de Polignac number, because none of the positive numbers 2k-20134202555 is a prime.
It is a super-2 number, since 2×201342025552 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5226380 + ... + 5230230.
It is an arithmetic number, because the mean of its divisors is an integer number (790430400).
Almost surely, 220134202555 is an apocalyptic number.
20134202555 is a deficient number, since it is larger than the sum of its proper divisors (5159570245).
20134202555 is a wasteful number, since it uses less digits than its factorization.
20134202555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4355.
The product of its (nonzero) digits is 12000, while the sum is 29.
Adding to 20134202555 its reverse (55520243102), we get a palindrome (75654445657).
The spelling of 20134202555 in words is "twenty billion, one hundred thirty-four million, two hundred two thousand, five hundred fifty-five".
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