Base | Representation |
---|---|
bin | 101101110001111010011110… |
… | …001010010101011011000000 |
3 | 222101220010020020210011001120 |
4 | 231301322132022111123000 |
5 | 202342242140341124300 |
6 | 1552115144154032240 |
7 | 60260326454504322 |
oct | 5561723612253300 |
9 | 871803206704046 |
10 | 201342130411200 |
11 | 59176799702a99 |
12 | 1a6b9554118680 |
13 | 88466349138cc |
14 | 37a10226a1612 |
15 | 1842586a1e3a0 |
hex | b71e9e2956c0 |
201342130411200 has 336 divisors, whose sum is σ = 666086591729664. Its totient is φ = 53243243827200.
The previous prime is 201342130411199. The next prime is 201342130411237. The reversal of 201342130411200 is 2114031243102.
201342130411200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1305076467 + ... + 1305230733.
It is an arithmetic number, because the mean of its divisors is an integer number (1982400570624).
Almost surely, 2201342130411200 is an apocalyptic number.
201342130411200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 201342130411200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (333043295864832).
201342130411200 is an abundant number, since it is smaller than the sum of its proper divisors (464744461318464).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
201342130411200 is a wasteful number, since it uses less digits than its factorization.
201342130411200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156560 (or 156545 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 201342130411200 its reverse (2114031243102), we get a palindrome (203456161654302).
The spelling of 201342130411200 in words is "two hundred one trillion, three hundred forty-two billion, one hundred thirty million, four hundred eleven thousand, two hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •