Base | Representation |
---|---|
bin | 10010110000000101… |
… | …111011101010100111 |
3 | 1220222012002001200011 |
4 | 102300011323222213 |
5 | 312213324324221 |
6 | 13125522031051 |
7 | 1311641666161 |
oct | 226005735247 |
9 | 56865061604 |
10 | 20134214311 |
11 | 85a226a242 |
12 | 3a9aaa8487 |
13 | 1b8b43a6a3 |
14 | d90061931 |
15 | 7cc92d1e1 |
hex | 4b017baa7 |
20134214311 has 2 divisors, whose sum is σ = 20134214312. Its totient is φ = 20134214310.
The previous prime is 20134214267. The next prime is 20134214323. The reversal of 20134214311 is 11341243102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20134214311 - 213 = 20134206119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20134214011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067107155 + 10067107156.
It is an arithmetic number, because the mean of its divisors is an integer number (10067107156).
Almost surely, 220134214311 is an apocalyptic number.
20134214311 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134214311 is an equidigital number, since it uses as much as digits as its factorization.
20134214311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 20134214311 its reverse (11341243102), we get a palindrome (31475457413).
The spelling of 20134214311 in words is "twenty billion, one hundred thirty-four million, two hundred fourteen thousand, three hundred eleven".
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