Base | Representation |
---|---|
bin | 1011101110000011110… |
… | …0101100010101101101 |
3 | 201020200220102212101002 |
4 | 2323200330230111231 |
5 | 11244322140033003 |
6 | 232255004330045 |
7 | 20355312013514 |
oct | 2734074542555 |
9 | 636626385332 |
10 | 201342502253 |
11 | 78430658aa2 |
12 | 33031243925 |
13 | 15ca94b88c9 |
14 | 9a6050767b |
15 | 538625ca88 |
hex | 2ee0f2c56d |
201342502253 has 2 divisors, whose sum is σ = 201342502254. Its totient is φ = 201342502252.
The previous prime is 201342502243. The next prime is 201342502307. The reversal of 201342502253 is 352205243102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 193386219049 + 7956283204 = 439757^2 + 89198^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201342502253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201342502243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671251126 + 100671251127.
It is an arithmetic number, because the mean of its divisors is an integer number (100671251127).
Almost surely, 2201342502253 is an apocalyptic number.
It is an amenable number.
201342502253 is a deficient number, since it is larger than the sum of its proper divisors (1).
201342502253 is an equidigital number, since it uses as much as digits as its factorization.
201342502253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 201342502253 its reverse (352205243102), we get a palindrome (553547745355).
The spelling of 201342502253 in words is "two hundred one billion, three hundred forty-two million, five hundred two thousand, two hundred fifty-three".
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