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201343323444022 = 2100671661722011
BaseRepresentation
bin101101110001111011100101…
…010001011001001100110110
3222101220020022101200111102101
4231301323211101121030312
5202342302111300202042
61552115502412532314
760260401152224164
oct5561734521311466
9871806271614371
10201343323444022
1159177251090231
121a6b982778109a
138846794b38aa6
1437a10d6cda234
1518426066306b7
hexb71ee5459336

201343323444022 has 4 divisors (see below), whose sum is σ = 302014985166036. Its totient is φ = 100671661722010.

The previous prime is 201343323443953. The next prime is 201343323444047. The reversal of 201343323444022 is 220444323343102.

201343323444022 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50335830861004 + ... + 50335830861007.

It is an arithmetic number, because the mean of its divisors is an integer number (75503746291509).

Almost surely, 2201343323444022 is an apocalyptic number.

201343323444022 is a deficient number, since it is larger than the sum of its proper divisors (100671661722014).

201343323444022 is a wasteful number, since it uses less digits than its factorization.

201343323444022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100671661722013.

The product of its (nonzero) digits is 331776, while the sum is 37.

Adding to 201343323444022 its reverse (220444323343102), we get a palindrome (421787646787124).

The spelling of 201343323444022 in words is "two hundred one trillion, three hundred forty-three billion, three hundred twenty-three million, four hundred forty-four thousand, twenty-two".

Divisors: 1 2 100671661722011 201343323444022