Base | Representation |
---|---|
bin | 101101110001111011100110… |
… | …011000111111011101100111 |
3 | 222101220020100201000001120111 |
4 | 231301323212120333131213 |
5 | 202342302131101303332 |
6 | 1552115504323113451 |
7 | 60260401500605143 |
oct | 5561734630773547 |
9 | 871806321001514 |
10 | 201343342212967 |
11 | 5917726073a659 |
12 | 1a6b9831b12887 |
13 | 88467989aaa86 |
14 | 37a10d95c4223 |
15 | 18426080db947 |
hex | b71ee663f767 |
201343342212967 has 2 divisors, whose sum is σ = 201343342212968. Its totient is φ = 201343342212966.
The previous prime is 201343342212917. The next prime is 201343342213019. The reversal of 201343342212967 is 769212243343102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 201343342212967 - 215 = 201343342180199 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201343342212967.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201343342212917) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100671671106483 + 100671671106484.
It is an arithmetic number, because the mean of its divisors is an integer number (100671671106484).
Almost surely, 2201343342212967 is an apocalyptic number.
201343342212967 is a deficient number, since it is larger than the sum of its proper divisors (1).
201343342212967 is an equidigital number, since it uses as much as digits as its factorization.
201343342212967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2612736, while the sum is 49.
The spelling of 201343342212967 in words is "two hundred one trillion, three hundred forty-three billion, three hundred forty-two million, two hundred twelve thousand, nine hundred sixty-seven".
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