20134344017 has 2 divisors, whose sum is σ = 20134344018. Its totient is φ = 20134344016.

The previous prime is 20134344011. The next prime is 20134344019. The reversal of 20134344017 is 71044343102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13573182016 + 6561162001 = 116504^2 + 81001^2 .

It is a cyclic number.

It is not a de Polignac number, because 20134344017 - 2¹² = 20134339921 is a prime.

Together with 20134344019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (20134344011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067172008 + 10067172009.

It is an arithmetic number, because the mean of its divisors is an integer number (10067172009).

Almost surely, 2^20134344017 is an apocalyptic number.

It is an amenable number.

20134344017 is a deficient number, since it is larger than the sum of its proper divisors (1).

20134344017 is an equidigital number, since it uses as much as digits as its factorization.

20134344017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 29.

Adding to 20134344017 its reverse (71044343102), we get a palindrome (91178687119).

The spelling of 20134344017 in words is "twenty billion, one hundred thirty-four million, three hundred forty-four thousand, seventeen".