20134401231 has 32 divisors (see below), whose sum is σ = 32494583808. Its totient is φ = 10825643520.

The previous prime is 20134401139. The next prime is 20134401247. The reversal of 20134401231 is 13210443102.

It is not a de Polignac number, because 20134401231 - 2¹⁰ = 20134400207 is a prime.

It is a super-2 number, since 2×20134401231² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a junction number, because it is equal to n+sod(n) for n = 20134401198 and 20134401207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20134421231) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2188461 + ... + 2197641.

It is an arithmetic number, because the mean of its divisors is an integer number (1015455744).

Almost surely, 2^20134401231 is an apocalyptic number.

20134401231 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

20134401231 is a deficient number, since it is larger than the sum of its proper divisors (12360182577).

20134401231 is a wasteful number, since it uses less digits than its factorization.

20134401231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15351.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 20134401231 its reverse (13210443102), we get a palindrome (33344844333).

The spelling of 20134401231 in words is "twenty billion, one hundred thirty-four million, four hundred one thousand, two hundred thirty-one".