Base | Representation |
---|---|
bin | 10010110000000110… |
… | …101001011111101111 |
3 | 1220222012102121011202 |
4 | 102300012221133233 |
5 | 312213401331111 |
6 | 13125530040115 |
7 | 1311643410362 |
oct | 226006513757 |
9 | 56865377152 |
10 | 20134402031 |
11 | 85a2388287 |
12 | 3a9ab7903b |
13 | 1b8b4a4c73 |
14 | d900b00d9 |
15 | 7cc968b3b |
hex | 4b01a97ef |
20134402031 has 4 divisors (see below), whose sum is σ = 20376985272. Its totient is φ = 19891818792.
The previous prime is 20134401983. The next prime is 20134402063. The reversal of 20134402031 is 13020443102.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13020443102 = 2 ⋅6510221551.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20134402031 is a prime.
It is a super-2 number, since 2×201344020312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20134401994 and 20134402012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20134402531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121291496 + ... + 121291661.
It is an arithmetic number, because the mean of its divisors is an integer number (5094246318).
Almost surely, 220134402031 is an apocalyptic number.
20134402031 is a deficient number, since it is larger than the sum of its proper divisors (242583241).
20134402031 is an equidigital number, since it uses as much as digits as its factorization.
20134402031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 242583240.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 20134402031 its reverse (13020443102), we get a palindrome (33154845133).
It can be divided in two parts, 2013 and 4402031, that added together give a palindrome (4404044).
The spelling of 20134402031 in words is "twenty billion, one hundred thirty-four million, four hundred two thousand, thirty-one".
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