Base | Representation |
---|---|
bin | 10010110000000110… |
… | …101100001001100001 |
3 | 1220222012110011002012 |
4 | 102300012230021201 |
5 | 312213402203042 |
6 | 13125530202305 |
7 | 1311643454144 |
oct | 226006541141 |
9 | 56865404065 |
10 | 20134412897 |
11 | 85a2395465 |
12 | 3a9ab83395 |
13 | 1b8b4a9bb1 |
14 | d900b405b |
15 | 7cc96be82 |
hex | 4b01ac261 |
20134412897 has 2 divisors, whose sum is σ = 20134412898. Its totient is φ = 20134412896.
The previous prime is 20134412891. The next prime is 20134413001. The reversal of 20134412897 is 79821443102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10246298176 + 9888114721 = 101224^2 + 99439^2 .
It is a cyclic number.
It is not a de Polignac number, because 20134412897 - 230 = 19060671073 is a prime.
It is not a weakly prime, because it can be changed into another prime (20134412891) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067206448 + 10067206449.
It is an arithmetic number, because the mean of its divisors is an integer number (10067206449).
Almost surely, 220134412897 is an apocalyptic number.
It is an amenable number.
20134412897 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134412897 is an equidigital number, since it uses as much as digits as its factorization.
20134412897 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 41.
Adding to 20134412897 its reverse (79821443102), we get a palindrome (99955855999).
The spelling of 20134412897 in words is "twenty billion, one hundred thirty-four million, four hundred twelve thousand, eight hundred ninety-seven".
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