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20134908645179 is a prime number
BaseRepresentation
bin1001001010000000001100…
…00100111100111100111011
32122021212201101212202120212
410211000012010330330323
510114342243103121204
6110453503242341335
74145461543416056
oct445000604747473
978255641782525
1020134908645179
116463192017a19
1223123441ba84b
13b3093810c633
144d876b607a9d
1524db4db07c6e
hex12500613cf3b

20134908645179 has 2 divisors, whose sum is σ = 20134908645180. Its totient is φ = 20134908645178.

The previous prime is 20134908645167. The next prime is 20134908645197. The reversal of 20134908645179 is 97154680943102.

It is a happy number.

Together with next prime (20134908645197) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20134908645179 - 220 = 20134907596603 is a prime.

It is a super-2 number, since 2×201349086451792 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (20134908645779) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067454322589 + 10067454322590.

It is an arithmetic number, because the mean of its divisors is an integer number (10067454322590).

It is a 2-persistent number, because it is pandigital, and so is 2⋅20134908645179 = 40269817290358, but 3⋅20134908645179 = 60404725935537 is not.

Almost surely, 220134908645179 is an apocalyptic number.

20134908645179 is a deficient number, since it is larger than the sum of its proper divisors (1).

20134908645179 is an equidigital number, since it uses as much as digits as its factorization.

20134908645179 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13063680, while the sum is 59.

The spelling of 20134908645179 in words is "twenty trillion, one hundred thirty-four billion, nine hundred eight million, six hundred forty-five thousand, one hundred seventy-nine".