Base | Representation |
---|---|
bin | 1011101110000101100… |
… | …1101110111100111011 |
3 | 201020201102202122021112 |
4 | 2323201121232330323 |
5 | 11244331112141011 |
6 | 232255435430535 |
7 | 20355433511504 |
oct | 2734131567473 |
9 | 636642678245 |
10 | 201350115131 |
11 | 78434988730 |
12 | 330338b544b |
13 | 15caac52a79 |
14 | 9a61529bab |
15 | 5386c6358b |
hex | 2ee166ef3b |
201350115131 has 32 divisors (see below), whose sum is σ = 225995616000. Its totient is φ = 177810554880.
The previous prime is 201350115107. The next prime is 201350115137. The reversal of 201350115131 is 131511053102.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201350115131 is a prime.
It is a super-2 number, since 2×2013501151312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 201350115097 and 201350115106.
It is not an unprimeable number, because it can be changed into a prime (201350115137) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 127516700 + ... + 127518278.
It is an arithmetic number, because the mean of its divisors is an integer number (7062363000).
Almost surely, 2201350115131 is an apocalyptic number.
201350115131 is a deficient number, since it is larger than the sum of its proper divisors (24645500869).
201350115131 is a wasteful number, since it uses less digits than its factorization.
201350115131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2939.
The product of its (nonzero) digits is 450, while the sum is 23.
Adding to 201350115131 its reverse (131511053102), we get a palindrome (332861168233).
The spelling of 201350115131 in words is "two hundred one billion, three hundred fifty million, one hundred fifteen thousand, one hundred thirty-one".
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