Base | Representation |
---|---|
bin | 1001001010000000011011… |
… | …00001000000100001101111 |
3 | 2122021220001002201000101212 |
4 | 10211000031201000201233 |
5 | 10114343022030042432 |
6 | 110453523501225035 |
7 | 4145464620231326 |
oct | 445001541004157 |
9 | 78256032630355 |
10 | 20135033440367 |
11 | 646324650443a |
12 | 2312379b6217b |
13 | b30957c25041 |
14 | 4d87800110bd |
15 | 24db59a592b2 |
hex | 12500d84086f |
20135033440367 has 2 divisors, whose sum is σ = 20135033440368. Its totient is φ = 20135033440366.
The previous prime is 20135033440363. The next prime is 20135033440381. The reversal of 20135033440367 is 76304433053102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20135033440367 - 22 = 20135033440363 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20135033440363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067516720183 + 10067516720184.
It is an arithmetic number, because the mean of its divisors is an integer number (10067516720184).
Almost surely, 220135033440367 is an apocalyptic number.
20135033440367 is a deficient number, since it is larger than the sum of its proper divisors (1).
20135033440367 is an equidigital number, since it uses as much as digits as its factorization.
20135033440367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 41.
Adding to 20135033440367 its reverse (76304433053102), we get a palindrome (96439466493469).
The spelling of 20135033440367 in words is "twenty trillion, one hundred thirty-five billion, thirty-three million, four hundred forty thousand, three hundred sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •