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2013520693 is a prime number
BaseRepresentation
bin111100000000011…
…1110001100110101
312012022210110010111
41320000332030311
513110430130233
6531444423021
7100616433502
oct17000761465
95168713114
102013520693
11943641998
124823a7a71
132611cc582
141515b84a9
15bbb83acd
hex7803e335

2013520693 has 2 divisors, whose sum is σ = 2013520694. Its totient is φ = 2013520692.

The previous prime is 2013520679. The next prime is 2013520739. The reversal of 2013520693 is 3960253102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1915550289 + 97970404 = 43767^2 + 9898^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013520693 - 25 = 2013520661 is a prime.

It is a super-2 number, since 2×20135206932 = 8108531162278400498, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013520633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006760346 + 1006760347.

It is an arithmetic number, because the mean of its divisors is an integer number (1006760347).

Almost surely, 22013520693 is an apocalyptic number.

It is an amenable number.

2013520693 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013520693 is an equidigital number, since it uses as much as digits as its factorization.

2013520693 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 31.

The square root of 2013520693 is about 44872.2708696585. The cubic root of 2013520693 is about 1262.7538435171.

Adding to 2013520693 its reverse (3960253102), we get a palindrome (5973773795).

The spelling of 2013520693 in words is "two billion, thirteen million, five hundred twenty thousand, six hundred ninety-three".