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20135441561 is a prime number
BaseRepresentation
bin10010110000001010…
…100111010010011001
31220222021101102010212
4102300022213102121
5312214133112221
613130004220505
71311655300154
oct226012472231
956867342125
1020135441561
1185a2a282a4
123a9b39a735
131b8b77a181
14d902a0c9b
157ccac1b5b
hex4b02a7499

20135441561 has 2 divisors, whose sum is σ = 20135441562. Its totient is φ = 20135441560.

The previous prime is 20135441533. The next prime is 20135441581. The reversal of 20135441561 is 16514453102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20119720336 + 15721225 = 141844^2 + 3965^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20135441561 is a prime.

It is a super-2 number, since 2×201354415612 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (20135441581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067720780 + 10067720781.

It is an arithmetic number, because the mean of its divisors is an integer number (10067720781).

Almost surely, 220135441561 is an apocalyptic number.

It is an amenable number.

20135441561 is a deficient number, since it is larger than the sum of its proper divisors (1).

20135441561 is an equidigital number, since it uses as much as digits as its factorization.

20135441561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 20135441561 its reverse (16514453102), we get a palindrome (36649894663).

The spelling of 20135441561 in words is "twenty billion, one hundred thirty-five million, four hundred forty-one thousand, five hundred sixty-one".