20135441533 has 2 divisors, whose sum is σ = 20135441534. Its totient is φ = 20135441532.

The previous prime is 20135441519. The next prime is 20135441561. The reversal of 20135441533 is 33514453102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19458297049 + 677144484 = 139493^2 + 26022^2 .

It is a cyclic number.

It is not a de Polignac number, because 20135441533 - 2¹³ = 20135433341 is a prime.

It is a super-2 number, since 2×20135441533² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20135441495 and 20135441504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20135444533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067720766 + 10067720767.

It is an arithmetic number, because the mean of its divisors is an integer number (10067720767).

Almost surely, 2^20135441533 is an apocalyptic number.

It is an amenable number.

20135441533 is a deficient number, since it is larger than the sum of its proper divisors (1).

20135441533 is an equidigital number, since it uses as much as digits as its factorization.

20135441533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 20135441533 its reverse (33514453102), we get a palindrome (53649894635).

The spelling of 20135441533 in words is "twenty billion, one hundred thirty-five million, four hundred forty-one thousand, five hundred thirty-three".