Base | Representation |
---|---|
bin | 1001001010000001110000… |
… | …10011110110100100110011 |
3 | 2122021221220010200202100112 |
4 | 10211000320103312210303 |
5 | 10114401004330141034 |
6 | 110454123030011535 |
7 | 4145521456003205 |
oct | 445007023664463 |
9 | 78257803622315 |
10 | 20135751412019 |
11 | 6463584809141 |
12 | 231253a4a6bab |
13 | b30a408b7539 |
14 | 4d880b506775 |
15 | 24db9cacb7ce |
hex | 1250384f6933 |
20135751412019 has 2 divisors, whose sum is σ = 20135751412020. Its totient is φ = 20135751412018.
The previous prime is 20135751411967. The next prime is 20135751412057. The reversal of 20135751412019 is 91021415753102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20135751412019 - 228 = 20135482976563 is a prime.
It is a super-2 number, since 2×201357514120192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20135751412319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067875706009 + 10067875706010.
It is an arithmetic number, because the mean of its divisors is an integer number (10067875706010).
Almost surely, 220135751412019 is an apocalyptic number.
20135751412019 is a deficient number, since it is larger than the sum of its proper divisors (1).
20135751412019 is an equidigital number, since it uses as much as digits as its factorization.
20135751412019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 41.
The spelling of 20135751412019 in words is "twenty trillion, one hundred thirty-five billion, seven hundred fifty-one million, four hundred twelve thousand, nineteen".
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