Base | Representation |
---|---|
bin | 1001001010000001110000… |
… | …10011110110100011111111 |
3 | 2122021221220010200202021121 |
4 | 10211000320103312203333 |
5 | 10114401004330140332 |
6 | 110454123030011411 |
7 | 4145521456003102 |
oct | 445007023664377 |
9 | 78257803622247 |
10 | 20135751411967 |
11 | 64635848090a4 |
12 | 231253a4a6b67 |
13 | b30a408b74c9 |
14 | 4d880b506739 |
15 | 24db9cacb797 |
hex | 1250384f68ff |
20135751411967 has 2 divisors, whose sum is σ = 20135751411968. Its totient is φ = 20135751411966.
The previous prime is 20135751411961. The next prime is 20135751412019. The reversal of 20135751411967 is 76911415753102.
It is an a-pointer prime, because the next prime (20135751412019) can be obtained adding 20135751411967 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20135751411967 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20135751411961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067875705983 + 10067875705984.
It is an arithmetic number, because the mean of its divisors is an integer number (10067875705984).
Almost surely, 220135751411967 is an apocalyptic number.
20135751411967 is a deficient number, since it is larger than the sum of its proper divisors (1).
20135751411967 is an equidigital number, since it uses as much as digits as its factorization.
20135751411967 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1587600, while the sum is 52.
The spelling of 20135751411967 in words is "twenty trillion, one hundred thirty-five billion, seven hundred fifty-one million, four hundred eleven thousand, nine hundred sixty-seven".
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