Base | Representation |
---|---|
bin | 11101010011101001001… |
… | …110110000110110000111 |
3 | 21010112101011122020102012 |
4 | 131103221032300312013 |
5 | 230444041124442233 |
6 | 4141111022004435 |
7 | 265334514423362 |
oct | 35235116606607 |
9 | 7115334566365 |
10 | 2013957655943 |
11 | 707129658332 |
12 | 28639a41671b |
13 | 117bb916879c |
14 | 6d6944a30d9 |
15 | 375c3549548 |
hex | 1d4e93b0d87 |
2013957655943 has 2 divisors, whose sum is σ = 2013957655944. Its totient is φ = 2013957655942.
The previous prime is 2013957655867. The next prime is 2013957655949. The reversal of 2013957655943 is 3495567593102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013957655943 - 220 = 2013956607367 is a prime.
It is a super-3 number, since 3×20139576559433 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013957655949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006978827971 + 1006978827972.
It is an arithmetic number, because the mean of its divisors is an integer number (1006978827972).
Almost surely, 22013957655943 is an apocalyptic number.
2013957655943 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013957655943 is an equidigital number, since it uses as much as digits as its factorization.
2013957655943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30618000, while the sum is 59.
The spelling of 2013957655943 in words is "two trillion, thirteen billion, nine hundred fifty-seven million, six hundred fifty-five thousand, nine hundred forty-three".
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