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201401432413 is a prime number
BaseRepresentation
bin1011101110010001110…
…1011111100101011101
3201020212000022211100121
42323210131133211131
511244432231314123
6232304511354541
720356625633536
oct2734435374535
9636760284317
10201401432413
1178460949105
1233048b22a51
1315cb877c91c
149a6828768d
15538b4ed75d
hex2ee475f95d

201401432413 has 2 divisors, whose sum is σ = 201401432414. Its totient is φ = 201401432412.

The previous prime is 201401432389. The next prime is 201401432417. The reversal of 201401432413 is 314234104102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107077509529 + 94323922884 = 327227^2 + 307122^2 .

It is a cyclic number.

It is not a de Polignac number, because 201401432413 - 221 = 201399335261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201401432417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100700716206 + 100700716207.

It is an arithmetic number, because the mean of its divisors is an integer number (100700716207).

Almost surely, 2201401432413 is an apocalyptic number.

It is an amenable number.

201401432413 is a deficient number, since it is larger than the sum of its proper divisors (1).

201401432413 is an equidigital number, since it uses as much as digits as its factorization.

201401432413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 201401432413 its reverse (314234104102), we get a palindrome (515635536515).

The spelling of 201401432413 in words is "two hundred one billion, four hundred one million, four hundred thirty-two thousand, four hundred thirteen".