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2014034204191 is a prime number
BaseRepresentation
bin11101010011101101110…
…010110001011000011111
321010112120111200021212111
4131103231302301120133
5230444220224013231
64141122354414451
7265336434162202
oct35235562613037
97115514607774
102014034204191
11707168891149
122863bbb91427
13117bcbc8a9c9
146d6a070b939
15375ca11a4b1
hex1d4edcb161f

2014034204191 has 2 divisors, whose sum is σ = 2014034204192. Its totient is φ = 2014034204190.

The previous prime is 2014034204093. The next prime is 2014034204249. The reversal of 2014034204191 is 1914024304102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2014034204191 - 217 = 2014034073119 is a prime.

It is a super-3 number, since 3×20140342041913 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2014034204491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007017102095 + 1007017102096.

It is an arithmetic number, because the mean of its divisors is an integer number (1007017102096).

Almost surely, 22014034204191 is an apocalyptic number.

2014034204191 is a deficient number, since it is larger than the sum of its proper divisors (1).

2014034204191 is an equidigital number, since it uses as much as digits as its factorization.

2014034204191 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 2014034204191 its reverse (1914024304102), we get a palindrome (3928058508293).

The spelling of 2014034204191 in words is "two trillion, fourteen billion, thirty-four million, two hundred four thousand, one hundred ninety-one".