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201404113 is a prime number
BaseRepresentation
bin11000000000100…
…10111011010001
3112000222101111121
430000102323101
5403024412423
631552442241
74663623001
oct1400227321
9460871447
10201404113
11a3761989
1257549381
1332959441
141ca6a001
1512a3545d
hexc012ed1

201404113 has 2 divisors, whose sum is σ = 201404114. Its totient is φ = 201404112.

The previous prime is 201404089. The next prime is 201404143. The reversal of 201404113 is 311404102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109474369 + 91929744 = 10463^2 + 9588^2 .

It is a cyclic number.

It is not a de Polignac number, because 201404113 - 217 = 201273041 is a prime.

It is not a weakly prime, because it can be changed into another prime (201404143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100702056 + 100702057.

It is an arithmetic number, because the mean of its divisors is an integer number (100702057).

Almost surely, 2201404113 is an apocalyptic number.

It is an amenable number.

201404113 is a deficient number, since it is larger than the sum of its proper divisors (1).

201404113 is an equidigital number, since it uses as much as digits as its factorization.

201404113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 201404113 is about 14191.6916891539. The cubic root of 201404113 is about 586.1689078495.

Adding to 201404113 its reverse (311404102), we get a palindrome (512808215).

The spelling of 201404113 in words is "two hundred one million, four hundred four thousand, one hundred thirteen".