Base | Representation |
---|---|
bin | 10010110000100000… |
… | …001101101111101111 |
3 | 1220222200001002200221 |
4 | 102300200031233233 |
5 | 312222110312421 |
6 | 13130325432211 |
7 | 1312054363102 |
oct | 226040155757 |
9 | 56880032627 |
10 | 20141104111 |
11 | 85a6145697 |
12 | 3aa126b667 |
13 | 1b8c9b06ab |
14 | d90d36739 |
15 | 7cd33e841 |
hex | 4b080dbef |
20141104111 has 2 divisors, whose sum is σ = 20141104112. Its totient is φ = 20141104110.
The previous prime is 20141104103. The next prime is 20141104129. The reversal of 20141104111 is 11140114102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20141104111 - 23 = 20141104103 is a prime.
It is a super-3 number, since 3×201411041113 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20141104211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10070552055 + 10070552056.
It is an arithmetic number, because the mean of its divisors is an integer number (10070552056).
Almost surely, 220141104111 is an apocalyptic number.
20141104111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20141104111 is an equidigital number, since it uses as much as digits as its factorization.
20141104111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 20141104111 its reverse (11140114102), we get a palindrome (31281218213).
Subtracting from 20141104111 its reverse (11140114102), we obtain a palindrome (9000990009).
The spelling of 20141104111 in words is "twenty billion, one hundred forty-one million, one hundred four thousand, one hundred eleven".
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