Base | Representation |
---|---|
bin | 1001001010001100100100… |
… | …01011000101110110001101 |
3 | 2122022111212112100101120011 |
4 | 10211012102023011312031 |
5 | 10114444400313011023 |
6 | 110500522512153221 |
7 | 4146115325315521 |
oct | 445062213056615 |
9 | 78274775311504 |
10 | 20141554032013 |
11 | 6465a92186457 |
12 | 2313699838811 |
13 | b31456b056ab |
14 | 4d8bdc015d81 |
15 | 24dddc22650d |
hex | 1251922c5d8d |
20141554032013 has 4 divisors (see below), whose sum is σ = 20141795496448. Its totient is φ = 20141312567580.
The previous prime is 20141554032007. The next prime is 20141554032031. The reversal of 20141554032013 is 31023045514102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20141554032013 - 25 = 20141554031981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20141554332013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120607053 + ... + 120773938.
It is an arithmetic number, because the mean of its divisors is an integer number (5035448874112).
Almost surely, 220141554032013 is an apocalyptic number.
It is an amenable number.
20141554032013 is a deficient number, since it is larger than the sum of its proper divisors (241464435).
20141554032013 is an equidigital number, since it uses as much as digits as its factorization.
20141554032013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241464434.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 20141554032013 its reverse (31023045514102), we get a palindrome (51164599546115).
The spelling of 20141554032013 in words is "twenty trillion, one hundred forty-one billion, five hundred fifty-four million, thirty-two thousand, thirteen".
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