Base | Representation |
---|---|
bin | 11101010011111001101… |
… | …110100000000101000111 |
3 | 21010120002110101212102220 |
4 | 131103321232200011013 |
5 | 231000123002130320 |
6 | 4141154305503423 |
7 | 265344415001406 |
oct | 35237156400507 |
9 | 7116073355386 |
10 | 2014234411335 |
11 | 7072608a57a3 |
12 | 286457041b73 |
13 | 117c315b8383 |
14 | 6d6bd14563d |
15 | 375dc9b5e40 |
hex | 1d4f9ba0147 |
2014234411335 has 16 divisors (see below), whose sum is σ = 3291344741376. Its totient is φ = 1051401791648.
The previous prime is 2014234411309. The next prime is 2014234411337. The reversal of 2014234411335 is 5331144324102.
It is a cyclic number.
It is not a de Polignac number, because 2014234411335 - 210 = 2014234410311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2014234411296 and 2014234411305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2014234411337) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1428534339 + ... + 1428535748.
It is an arithmetic number, because the mean of its divisors is an integer number (205709046336).
Almost surely, 22014234411335 is an apocalyptic number.
2014234411335 is a deficient number, since it is larger than the sum of its proper divisors (1277110330041).
2014234411335 is a wasteful number, since it uses less digits than its factorization.
2014234411335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2857070142.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 2014234411335 its reverse (5331144324102), we get a palindrome (7345378735437).
The spelling of 2014234411335 in words is "two trillion, fourteen billion, two hundred thirty-four million, four hundred eleven thousand, three hundred thirty-five".
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