Base | Representation |
---|---|
bin | 1001001010001110001110… |
… | …00011110001010001011001 |
3 | 2122022121011100220112112012 |
4 | 10211013013003301101121 |
5 | 10120003204433231202 |
6 | 110501150525355305 |
7 | 4146146321106662 |
oct | 445070703612131 |
9 | 78277140815465 |
10 | 20142441305177 |
11 | 64663a8005964 |
12 | 23138a6a08b35 |
13 | b315688942b9 |
14 | 4d8c83bbc369 |
15 | 24de4008c152 |
hex | 1251c70f1459 |
20142441305177 has 2 divisors, whose sum is σ = 20142441305178. Its totient is φ = 20142441305176.
The previous prime is 20142441305171. The next prime is 20142441305179. The reversal of 20142441305177 is 77150314424102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19962407420761 + 180033884416 = 4467931^2 + 424304^2 .
It is a cyclic number.
It is not a de Polignac number, because 20142441305177 - 26 = 20142441305113 is a prime.
Together with 20142441305179, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20142441305171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10071220652588 + 10071220652589.
It is an arithmetic number, because the mean of its divisors is an integer number (10071220652589).
Almost surely, 220142441305177 is an apocalyptic number.
It is an amenable number.
20142441305177 is a deficient number, since it is larger than the sum of its proper divisors (1).
20142441305177 is an equidigital number, since it uses as much as digits as its factorization.
20142441305177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 188160, while the sum is 41.
Adding to 20142441305177 its reverse (77150314424102), we get a palindrome (97292755729279).
The spelling of 20142441305177 in words is "twenty trillion, one hundred forty-two billion, four hundred forty-one million, three hundred five thousand, one hundred seventy-seven".
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