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20143011315042 = 232711236716357859
BaseRepresentation
bin1001001010001111010010…
…00010001011110101100010
32122022122122002111001001200
410211013221002023311202
510120010341344040132
6110501323250542030
74146166412111220
oct445075102136542
978278562431050
1020143011315042
11646666a83a7a0
122313a25897916
13b316299bc545
144d8cd9799b10
1524de75133d7c
hex1251e908bd62

20143011315042 has 384 divisors, whose sum is σ = 57980008120320. Its totient is φ = 4899452469120.

The previous prime is 20143011315041. The next prime is 20143011315199. The reversal of 20143011315042 is 24051311034102.

20143011315042 is a `hidden beast` number, since 2 + 0 + 1 + 4 + 301 + 1 + 315 + 0 + 42 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 20143011314997 and 20143011315015.

It is not an unprimeable number, because it can be changed into a prime (20143011315041) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 348110709 + ... + 348168567.

It is an arithmetic number, because the mean of its divisors is an integer number (150989604480).

Almost surely, 220143011315042 is an apocalyptic number.

20143011315042 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 20143011315042, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (28990004060160).

20143011315042 is an abundant number, since it is smaller than the sum of its proper divisors (37836996805278).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20143011315042 is a wasteful number, since it uses less digits than its factorization.

20143011315042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58138 (or 58135 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 20143011315042 its reverse (24051311034102), we get a palindrome (44194322349144).

The spelling of 20143011315042 in words is "twenty trillion, one hundred forty-three billion, eleven million, three hundred fifteen thousand, forty-two".