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2014402114132 = 22677516425799
BaseRepresentation
bin11101010100000011101…
…110001111001001010100
321010120112010222001102121
4131110003232033021110
5231000443420123012
64141223100145324
7265351522312012
oct35240356171124
97116463861377
102014402114132
11707337529351
122864a3238244
13117c5a274bb5
146d6d751b8b2
15375ec590a07
hex1d503b8f254

2014402114132 has 12 divisors (see below), whose sum is σ = 3577818680800. Its totient is φ = 992168205336.

The previous prime is 2014402114117. The next prime is 2014402114139. The reversal of 2014402114132 is 2314112044102.

It is a super-2 number, since 2×20144021141322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2014402114097 and 2014402114106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2014402114139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3758212632 + ... + 3758213167.

Almost surely, 22014402114132 is an apocalyptic number.

It is an amenable number.

2014402114132 is a deficient number, since it is larger than the sum of its proper divisors (1563416566668).

2014402114132 is a wasteful number, since it uses less digits than its factorization.

2014402114132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7516425870 (or 7516425868 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2014402114132 its reverse (2314112044102), we get a palindrome (4328514158234).

The spelling of 2014402114132 in words is "two trillion, fourteen billion, four hundred two million, one hundred fourteen thousand, one hundred thirty-two".

Divisors: 1 2 4 67 134 268 7516425799 15032851598 30065703196 503600528533 1007201057066 2014402114132