Base | Representation |
---|---|
bin | 10010110000101011… |
… | …101100000110100001 |
3 | 1220222212200220210110 |
4 | 102300223230012201 |
5 | 312223343041113 |
6 | 13130514121533 |
7 | 1312122061413 |
oct | 226053540641 |
9 | 56885626713 |
10 | 20144112033 |
11 | 85a790a581 |
12 | 3aa22802a9 |
13 | 1b904c4826 |
14 | d914ba9b3 |
15 | 7cd735bc3 |
hex | 4b0aec1a1 |
20144112033 has 4 divisors (see below), whose sum is σ = 26858816048. Its totient is φ = 13429408020.
The previous prime is 20144112019. The next prime is 20144112047. The reversal of 20144112033 is 33021144102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (20144112019) and next prime (20144112047).
It is not a de Polignac number, because 20144112033 - 24 = 20144112017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20144112013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3357352003 + ... + 3357352008.
It is an arithmetic number, because the mean of its divisors is an integer number (6714704012).
Almost surely, 220144112033 is an apocalyptic number.
It is an amenable number.
20144112033 is a deficient number, since it is larger than the sum of its proper divisors (6714704015).
20144112033 is an equidigital number, since it uses as much as digits as its factorization.
20144112033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6714704014.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 20144112033 its reverse (33021144102), we get a palindrome (53165256135).
The spelling of 20144112033 in words is "twenty billion, one hundred forty-four million, one hundred twelve thousand, thirty-three".
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