20144112017 has 2 divisors, whose sum is σ = 20144112018. Its totient is φ = 20144112016.

The previous prime is 20144112013. The next prime is 20144112019. The reversal of 20144112017 is 71021144102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18277958416 + 1866153601 = 135196^2 + 43199^2 .

It is a cyclic number.

It is not a de Polignac number, because 20144112017 - 2² = 20144112013 is a prime.

Together with 20144112019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 20144111983 and 20144112001.

It is not a weakly prime, because it can be changed into another prime (20144112013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072056008 + 10072056009.

It is an arithmetic number, because the mean of its divisors is an integer number (10072056009).

Almost surely, 2^20144112017 is an apocalyptic number.

It is an amenable number.

20144112017 is a deficient number, since it is larger than the sum of its proper divisors (1).

20144112017 is an equidigital number, since it uses as much as digits as its factorization.

20144112017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 20144112017 its reverse (71021144102), we get a palindrome (91165256119).

The spelling of 20144112017 in words is "twenty billion, one hundred forty-four million, one hundred twelve thousand, seventeen".