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20144833 is a prime number
BaseRepresentation
bin100110011011…
…0001011000001
31101220110111221
41030312023001
520124113313
61555435041
7333141202
oct114661301
941813457
1020144833
111040a125
1268b5a81
134234327
1429655a9
151b7dc8d
hex13362c1

20144833 has 2 divisors, whose sum is σ = 20144834. Its totient is φ = 20144832.

The previous prime is 20144819. The next prime is 20144837. The reversal of 20144833 is 33844102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20133169 + 11664 = 4487^2 + 108^2 .

It is a cyclic number.

It is not a de Polignac number, because 20144833 - 29 = 20144321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20144798 and 20144807.

It is not a weakly prime, because it can be changed into another prime (20144837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10072416 + 10072417.

It is an arithmetic number, because the mean of its divisors is an integer number (10072417).

Almost surely, 220144833 is an apocalyptic number.

It is an amenable number.

20144833 is a deficient number, since it is larger than the sum of its proper divisors (1).

20144833 is an equidigital number, since it uses as much as digits as its factorization.

20144833 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 20144833 is about 4488.2995666510. The cubic root of 20144833 is about 272.0954150908.

Adding to 20144833 its reverse (33844102), we get a palindrome (53988935).

The spelling of 20144833 in words is "twenty million, one hundred forty-four thousand, eight hundred thirty-three".