201501511331 has 2 divisors, whose sum is σ = 201501511332. Its totient is φ = 201501511330.

The previous prime is 201501511213. The next prime is 201501511363. The reversal of 201501511331 is 133115105102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201501511331 - 2¹⁰ = 201501510307 is a prime.

It is a super-2 number, since 2×201501511331² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201501511297 and 201501511306.

It is not a weakly prime, because it can be changed into another prime (201501511531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100750755665 + 100750755666.

It is an arithmetic number, because the mean of its divisors is an integer number (100750755666).

Almost surely, 2^201501511331 is an apocalyptic number.

201501511331 is a deficient number, since it is larger than the sum of its proper divisors (1).

201501511331 is an equidigital number, since it uses as much as digits as its factorization.

201501511331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 201501511331 its reverse (133115105102), we get a palindrome (334616616433).

The spelling of 201501511331 in words is "two hundred one billion, five hundred one million, five hundred eleven thousand, three hundred thirty-one".