Base | Representation |
---|---|
bin | 11101010100101001111… |
… | …111110011100111010001 |
3 | 21010122011220021010221122 |
4 | 131110221333303213101 |
5 | 231003302312113121 |
6 | 4141410515332025 |
7 | 265403450361251 |
oct | 35245177634721 |
9 | 7118156233848 |
10 | 2015044254161 |
11 | 707636a49694 |
12 | 2866422b1015 |
13 | 118030306403 |
14 | 6d758913961 |
15 | 37638b345ab |
hex | 1d529ff39d1 |
2015044254161 has 2 divisors, whose sum is σ = 2015044254162. Its totient is φ = 2015044254160.
The previous prime is 2015044254107. The next prime is 2015044254163. The reversal of 2015044254161 is 1614524405102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1638976050625 + 376068203536 = 1280225^2 + 613244^2 .
It is a cyclic number.
It is not a de Polignac number, because 2015044254161 - 234 = 1997864384977 is a prime.
Together with 2015044254163, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2015044254163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007522127080 + 1007522127081.
It is an arithmetic number, because the mean of its divisors is an integer number (1007522127081).
Almost surely, 22015044254161 is an apocalyptic number.
It is an amenable number.
2015044254161 is a deficient number, since it is larger than the sum of its proper divisors (1).
2015044254161 is an equidigital number, since it uses as much as digits as its factorization.
2015044254161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 2015044254161 its reverse (1614524405102), we get a palindrome (3629568659263).
The spelling of 2015044254161 in words is "two trillion, fifteen billion, forty-four million, two hundred fifty-four thousand, one hundred sixty-one".
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