Base | Representation |
---|---|
bin | 11101010100101111111… |
… | …001110011110001000111 |
3 | 21010122102210201111022222 |
4 | 131110233321303301013 |
5 | 231004003144021343 |
6 | 4141424415242555 |
7 | 265406062546421 |
oct | 35245771636107 |
9 | 7118383644288 |
10 | 2015143345223 |
11 | 70768797a228 |
12 | 28666b51945b |
13 | 1180479bc288 |
14 | 6d767b49811 |
15 | 376426a9a68 |
hex | 1d52fe73c47 |
2015143345223 has 2 divisors, whose sum is σ = 2015143345224. Its totient is φ = 2015143345222.
The previous prime is 2015143345183. The next prime is 2015143345283. The reversal of 2015143345223 is 3225433415102.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2015143345223 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2015143345283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1007571672611 + 1007571672612.
It is an arithmetic number, because the mean of its divisors is an integer number (1007571672612).
Almost surely, 22015143345223 is an apocalyptic number.
2015143345223 is a deficient number, since it is larger than the sum of its proper divisors (1).
2015143345223 is an equidigital number, since it uses as much as digits as its factorization.
2015143345223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 2015143345223 in words is "two trillion, fifteen billion, one hundred forty-three million, three hundred forty-five thousand, two hundred twenty-three".
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