2015150113 has 4 divisors (see below), whose sum is σ = 2015364528. Its totient is φ = 2014935700.

The previous prime is 2015150077. The next prime is 2015150117. The reversal of 2015150113 is 3110515102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2015150113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2015150117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92431 + ... + 112132.

It is an arithmetic number, because the mean of its divisors is an integer number (503841132).

Almost surely, 2^2015150113 is an apocalyptic number.

It is an amenable number.

2015150113 is a deficient number, since it is larger than the sum of its proper divisors (214415).

2015150113 is an equidigital number, since it uses as much as digits as its factorization.

2015150113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 214414.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 2015150113 is about 44890.4233996517. The cubic root of 2015150113 is about 1263.0943750060.

Adding to 2015150113 its reverse (3110515102), we get a palindrome (5125665215).

The spelling of 2015150113 in words is "two billion, fifteen million, one hundred fifty thousand, one hundred thirteen".