Base | Representation |
---|---|
bin | 10010110001001001… |
… | …110010101101100001 |
3 | 1221000102112211202020 |
4 | 102301021302231201 |
5 | 312232403102200 |
6 | 13131355212053 |
7 | 1312246126401 |
oct | 226111625541 |
9 | 57012484666 |
10 | 20152003425 |
11 | 860130a494 |
12 | 3aa4a47029 |
13 | 1b920286a8 |
14 | d92572801 |
15 | 7ce293ea0 |
hex | 4b1272b61 |
20152003425 has 12 divisors (see below), whose sum is σ = 33317979120. Its totient is φ = 10747735120.
The previous prime is 20152003411. The next prime is 20152003441. The reversal of 20152003425 is 52430025102.
It is not a de Polignac number, because 20152003425 - 24 = 20152003409 is a prime.
It is a super-2 number, since 2×201520034252 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20152003395 and 20152003404.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 134346615 + ... + 134346764.
It is an arithmetic number, because the mean of its divisors is an integer number (2776498260).
Almost surely, 220152003425 is an apocalyptic number.
20152003425 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
20152003425 is a deficient number, since it is larger than the sum of its proper divisors (13165975695).
20152003425 is a wasteful number, since it uses less digits than its factorization.
20152003425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 268693392 (or 268693387 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 24.
Adding to 20152003425 its reverse (52430025102), we get a palindrome (72582028527).
The spelling of 20152003425 in words is "twenty billion, one hundred fifty-two million, three thousand, four hundred twenty-five".
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