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20152441141 = 72596970751
BaseRepresentation
bin10010110001001011…
…011101100100110101
31221000110101002011221
4102301023131210311
5312233011104031
613131412430341
71312252631500
oct226113354465
957013332157
1020152441141
118601589338
123aa50183b1
131b9214c9b1
14d92648137
157ce32da11
hex4b12dd935

20152441141 has 12 divisors (see below), whose sum is σ = 23839971840. Its totient is φ = 16980747000.

The previous prime is 20152441123. The next prime is 20152441151. The reversal of 20152441141 is 14114425102.

It is not a de Polignac number, because 20152441141 - 25 = 20152441109 is a prime.

It is a super-2 number, since 2×201524411412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20152441151) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3482485 + ... + 3488266.

It is an arithmetic number, because the mean of its divisors is an integer number (1986664320).

Almost surely, 220152441141 is an apocalyptic number.

It is an amenable number.

20152441141 is a deficient number, since it is larger than the sum of its proper divisors (3687530699).

20152441141 is an equidigital number, since it uses as much as digits as its factorization.

20152441141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6970824 (or 6970817 counting only the distinct ones).

The product of its (nonzero) digits is 1280, while the sum is 25.

Adding to 20152441141 its reverse (14114425102), we get a palindrome (34266866243).

The spelling of 20152441141 in words is "twenty billion, one hundred fifty-two million, four hundred forty-one thousand, one hundred forty-one".

Divisors: 1 7 49 59 413 2891 6970751 48795257 341566799 411274309 2878920163 20152441141