Base | Representation |
---|---|
bin | 1001001010100001111010… |
… | …01101101101000010000011 |
3 | 2122100121110011110111021201 |
4 | 10211100331031231002003 |
5 | 10120141332432232311 |
6 | 110510055553402031 |
7 | 4150002314543506 |
oct | 445207515550203 |
9 | 78317404414251 |
10 | 20153013555331 |
11 | 646a932844988 |
12 | 2315957569317 |
13 | b32561cb2617 |
14 | 4d95a7d4313d |
15 | 24e35d2d59c1 |
hex | 12543d36d083 |
20153013555331 has 2 divisors, whose sum is σ = 20153013555332. Its totient is φ = 20153013555330.
The previous prime is 20153013555329. The next prime is 20153013555343. The reversal of 20153013555331 is 13355531035102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20153013555331 - 21 = 20153013555329 is a prime.
It is a super-2 number, since 2×201530135553312 (a number of 27 digits) contains 22 as substring.
Together with 20153013555329, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (20153013555391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10076506777665 + 10076506777666.
It is an arithmetic number, because the mean of its divisors is an integer number (10076506777666).
Almost surely, 220153013555331 is an apocalyptic number.
20153013555331 is a deficient number, since it is larger than the sum of its proper divisors (1).
20153013555331 is an equidigital number, since it uses as much as digits as its factorization.
20153013555331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 101250, while the sum is 37.
The spelling of 20153013555331 in words is "twenty trillion, one hundred fifty-three billion, thirteen million, five hundred fifty-five thousand, three hundred thirty-one".
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